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**avendi** · 11-12-2007, 01:37 AM

x=1?

**wrichards2005** · 11-12-2007, 01:45 AM

x=7 yo

i'm pretty sure

i plugged it back in and it worked.

**wrichards2005** · 11-12-2007, 01:47 AM

1 + (2/7) = 3(^2)/7)

7/7 + (2/7) = 9/7

9/7 = 9/7

**wrichards2005** · 11-12-2007, 01:48 AM

wait is it x thats squared, or the whole fraction on the right, if its just x, then i'm wrong.

**avendi** · 11-12-2007, 01:53 AM

Originally posted by wrichards2005

wait is it x thats squared, or the whole fraction on the right, if its just x, then i'm wrong.

according to the way he wrote it, it would be just x unless the ^2 was on the outside of the parenthesis.

**elositocandela** · 11-12-2007, 02:01 AM

ok so its 7 but how did you get it? what method did you use?

**wrichards2005** · 11-12-2007, 02:05 AM

first you gotta answer if JUST the X is squared, if it is just the x then I did it wrong!

**elositocandela** · 11-12-2007, 02:10 AM

**wrichards2005** · 11-12-2007, 02:11 AM

ok i read it wrong. let me do it again.

**elositocandela** · 11-12-2007, 02:14 AM

how do you do it? that's the question... lol i dont want the answer i just want to know the steps so i can understand it

**wrichards2005** · 11-12-2007, 02:17 AM

ok its trickier now since the equation is changed. let me write my math on paint and see if its right.

**blizzard335** · 11-12-2007, 02:19 AM

multiply by x square.

then rearrange into a quadratic equation

u'll get

Xsq + 2X - 3 = 0

(x-1)(x+3).

**wrichards2005** · 11-12-2007, 02:24 AM

he's right

Its been 3 years since i've done that shit.

Thanks blizz

**elositocandela** · 11-12-2007, 02:27 AM

so x =1 i plug it in and it works it cant be -3 since it doesn't work

help algebra problem!