[HELP!!!] Calc test!!!

[elositocandela]

In CAlc you can have zero in the denom. when finding limits. Most times you use L'Hositals rule or multiple the whole thing by the inverse/ reciprocal of the numerator. So, is there any other info? L'Hosiptal rule states sum'um like if you have lim as.. Zero divided by Zero... Then use that rule. Wait I'll go look at my book.

now i remember i have to take the deriv. of the top divided by the deriv of the buttom.

[Straight Success]

Use the chain rule for the second one. f(x)g'(x)+f'(x)g(x).

[Straight Success]

x times e to the x is: f'(x)= 1, g(x)= e to the x, +, f(x)= x, g'(x)= e to the x.

[elositocandela]

ok i got there so far now it's asking to find if it has a point of inflection

[The G-Man]

Use the chain rule for the second one. f(x)g'(x)+f'(x)g(x).

That is not the chain rule, that is the multiplication one.

Chain rule is f'(g'(x))

[elositocandela]

do i have to set it equal to Y? And then solve for y?

[d2privat11]

Product rule: f(x)*g'(x)+ f '(x) * g(x)
f(x) = x * e^x
f'(x) = x *e^x + e^x

And I don't believe it has any inflections points (points at which the graph changes concavity, i.e. concave up to concave down). Use your graphing calculator!

[Straight Success]

My bad (I sometimes rush) but I still get A's.
Here ya go:

Chain Rule = f'(x)(g(x))g'(x)
Multi. Rule = f'(x)g(x)+f(x)g'(x)
Quot. Rule = f'(x)g(x)-f(x)g'(x)/g(x)^2
Inflection Points are found by finding a (c) critical number.
Then evaluate your entire domain at your (c)'s to find where the the graph's derivative shifts from positive to negative or vice versa. That's an inflection point. I think, this is right. Haven't used it in a while. This should be right.

[Straight Success]

Product rule: f(x)*g'(x)+ f '(x) * g(x)
f(x) = x * e^x
f'(x) = x *e^x + e^x

And I don't believe it has any inflections points (points at which the graph changes concavity, i.e. concave up to concave down). Use your graphing calculator!

f (x) = x * e^x
df/dx = x * e^x + e^x

Yea I know he put it, this is just a confirmation. My bad for the mishap.

[Straight Success]

One tip, anytime you solve for Y, that is called implicit differentiation. Not for this problem you dont. Unless they specifically ask you to differentiatte it that way.

[yoshi_h22a]

this brings back some highschool memories. the only thing that i remember vividly is the definition of a derivative. that was 7 years ago. sorry, i'm not much help now. goodluck bro.

[wed3k]

no wonder i failed CalCII twice...i dont even remember how to do this shit

[AccordWarrior]

http://integrals.wolfram.com/index.jsp

I lived off that in college math.

Searching Google is key...and that's why I'm a semester away from being an engimaneer, it's my research skills.

[wed3k]

http://integrals.wolfram.com/index.jsp

I lived off that in college math.

Searching Google is key...and that's why I'm a semester away from being an engimaneer, it's my research skills.

ho-lee-shit

[Straight Success]

Calc II is much tougher and an extremely fatser pace than Calc I. But I'm maintaining.