More HW help . . .

[DA92CB7]

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=10-x2. What are the dimensions of such a rectangle with the greatest possible area?

this we were kinda working on in class today but I didn't catch the first part of it when the teacher was talking, but from what I gather you take the base and call it 2x because it is divided equally by the y axis, but after that I wasn't sure where to go from there

[deevergote]

If I do your homework for you, will they put my name on your degree?



I'm useless with math... I only got a B+ in calculus because the professor curved up from a 40. I kicked ass in geometry, but that was 15 years ago (holy shit... really? damn I feel old...) I just wanted to be a smartass. Good luck!

[Straight Success]

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=10-x2. What are the dimensions of such a rectangle with the greatest possible area?

this we were kinda working on in class today but I didn't catch the first part of it when the teacher was talking, but from what I gather you take the base and call it 2x because it is divided equally by the y axis, but after that I wasn't sure where to go from there

Give me a second. I'll work through it with you, hold on...

[Straight Success]

First thing to realize is where the parabola intersects the x-axis. So first, figure out the two coordinates where the parabola intersects the x-axis and show me your answer.

[DA92CB7]

if you have msn we can draw it out i am gonna go take my dog on a walk ill be back in like 30 mins, but thanks man.

[Straight Success]

Okay.

[DA92CB7]

ok my msn is posted under my sn so just hit me up on there or windows live is what it is called actually.

[DA92CB7]

the co-ordinates where the parabola cross the y-axis are -3.162278,0 an 3.162278,0 since the parabolas cut in half by the y axis these points are reciprocals of each other so there was no need to find both just one.

[Straight Success]

Correct, same as (10)^(1/2) or +/- Root 10.

Now maximize the parabola. I believe you know how to do this using calculus. Plainly put, find the area under the parabola. This will be the absolute possible area for the window or what ever it is. Although a rectangle can't fully conceal all of the space inside of the parabola, it will help us a little.

[ibr_adam09]

Correct, same as (10)^(1/2) or +/- Root 10.

Now maximize the parabola. I believe you know how to do this using calculus. Plainly put, find the area under the parabola. This will be the absolute possible area for the window or what ever it is. Although a rectangle can't fully conceal all of the space inside of the parabola, it will help us a little.

Perfect user-name, .

[Straight Success]

Perfect user-name, .

What do you mean?

[DA92CB7]

that I don't know how to do we are just supposed to figure out a way to put two equations together so we can solve for a single variable. I am not in calc yet btw

[Straight Success]

that I don't know how to do we are just supposed to figure out a way to put two equations together so we can solve for a single variable. I am not in calc yet btw

What class is this for, physics, geometry, ...?

[Straight Success]

Okay, I see you're in pre-Calc. We can do this the geometric way. Are you ready?

[DA92CB7]

its pre calc 1